True/False

A pharmacy technician is calculating the decay rate kk for a radioactive medical sample with a half-life of {}9.45 minutes using the exponential decay model A=A0ektA = A_0 e^{kt}. To find kk, the technician first sets up the equation 0.5=e9.45k{}0.5 = e^{9.45k}. True or False: Taking the natural logarithm of both sides of this equation yields ln0.5=9.45k\ln 0.5 = 9.45k.

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Updated 2026-06-02

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